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bash
shell
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🔍 See Original Answer on Stack Overflow ⧉ 🔗
URL:
https://stackoverflow.com/q/62481189
Title:
How to convert w command idle timeout in seconds?
ID:
/2020/06/20/How-to-convert-w-command-idle-timeout-in-seconds_
Created:
June 20, 2020
Edited: June 20, 2020
Upload:
April 8, 2024
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Here is a bash solution:
WishSeconds () {
# PARM 1: 'w' command idle time 44.00s, 5:10, 1:28m, 3days, etc.
# 2: Variable name (no $ is used) to receive idel time in seconds
# NOTE: Idle time resets to zero when user types something in terminal.
# A looping job calling a command doesn't reset idle time.
local Wish Unit1 Unit2
Wish="$1"
declare -n Seconds=$2
# Leading 0 is considered octal value in bash. Change ':09' to ':9'
Wish="${Wish/:0/:}"
if [[ "$Wish" == *"days"* ]] ; then
Unit1="${Wish%%days*}"
Seconds=$(( Unit1 * 86400 ))
elif [[ "$Wish" == *"m"* ]] ; then
Unit1="${Wish%%m*}"
Unit2="${Unit1##*:}"
Unit1="${Unit1%%:*}"
Seconds=$(( (Unit1 * 3600) + (Unit2 * 60) ))
elif [[ "$Wish" == *"s"* ]] ; then
Seconds="${Wish%%.*}"
else
Unit1="${Wish%%:*}"
Unit2="${Wish##*:}"
Seconds=$(( (Unit1 * 60) + Unit2 ))
fi
} # WishSeconds
WishSeconds "20days" Days ; echo Passing 20days: $Days
WishSeconds "1:10m" Hours ; echo Passing 1:10m: $Hours
WishSeconds "1:30" Mins ; echo Passing 1:30: $Mins
WishSeconds "44.20s" Secs ; echo Passing 44.20s: $Secs
Results
Passing 20days: 1728000
Passing 1:10m: 4200
Passing 1:30: 90
Passing 44.20s: 44
Note
Instead of using:
w | tr -s " " | cut -d" " -f1,5 | tail -n+3
You can chop off the tail and use:
w -h | tr -s " " | cut -d" " -f1,5
This will remove the headers for you. I do the same plus use short format (sans CPU stats) and IP addresses instead of host names so I use:
w -ish | tr -s " " | cut -d" " -f1,5
Use man w for more argument details.